TJ solved a quadratic equation. His work is shown below, with Step 3 missing.
What could TJ have written as the result from Step 3?
2(x+6)2 – 5 = 45
2(x + 6)2 = 50
Step 1
(x + 6)2 = 25
Step 2
Step 3
=-11 or r=-1 Step 4

The value of x are -11 and -1.

Step-by-step explanation:

The quadratic equation is:

2 (x + 6)² - 5 = 45

Compute the value of x as follows:

2 (x + 6)² - 5 = 45

2 (x + 6)² = 50

(x + 6)² = 25

x² + 12x + 36 = 25

x² + 12x + 11 = 0

x² + 11x + x + 11 = 0

x (x + 11) + 1 (x + 11) = 0

(x + 11) (x + 1) = 0

If (x + 11) = 0, then x = -11.

If (x + 1) = 0, then x = -1.

Thus, the value of x are -11 and -1.

step-by-step explanation:

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

then, given the following line:

so,

we are looking for m_ {2}:

then, the line is given by:

we find "b" replacing the given point:

finally, the equation is:

option c