A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be x¯=$14.50 . Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is σ=$3.50 . To address the CEO’s conjecture, the marketing manager carried out a test of the hypothesis H0:µ=13.50 vs. H:µ>13.50 and obtained a P ‑value of p=0.077 .This result is significant at:

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

where is abdul's work? don't see that anywhere posted : /

step-by-step explanation:

5: 20

step-by-step explanation:

a. (14,375+570)(5.3) b. 158,417$

step-by-step explanation:

a. you are basically just setting up the equation. f= amount of debt hence 14,375. g= how much she is borrowing from her parents weekly hence 570 and t= the interest on her debt. creating the equation.

b.   14,375+570= 14,945

      14,945 x 5.3 = 79,208.5

      79,208.5 x 2(years) = 158,417(answer)