The sum of three consecutive numbers is greater than 40. The inequality that represents this is x + x + 1 + x + 2 > 40. Which values of x hold true for the inequality?

3x ＞ 37

x ＞ 12.333

Thus, 13 and 15 satisfy

Step-by-step explanation:

hope this helps

All integers greater than 12 (13 onwards) satisfy the inequality

Step-by-step explanation:

x + x + 1 + x + 2 > 40.

3x + 3 > 40

3x > 37

x > 12.3333

All integers greater than 12 (13 onwards) satisfy the inequality

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3