Triangle PQR with side p across from angle P, side q across from angle Q, and side r across from angle R

If ∠P measures 27°, q equals 6.0, and r equals 7.2, then which length can be found using the Law of Cosines?

r
q
RQ
PQ

R

Step-by-step explanation:

Law of cosine expression for the triangle will be

q² = r² + p² - 2 (rp) cos Q

going by the equation r and p is given and Q is included then we can calculate q which corresponds tor R which faces or is subtended by angle Q. p correspond to RQ and r correspond to PQ

its a straight line parallel to the time axis