To catch a frisbee, a dog leaps into air with an initial velocity of 14 feet per second. Write a model for the height of the dog above the ground. After how many seconds does the dog land on the ground?

Model:

The dog land on the ground after 0.8706 seconds.

Step-by-step explanation:

The model that said the height of the dog above the ground is a model of uniform acceleration motion, so it is:

Where is the initial height, is the initial velocity and is the gravity.

So, replacing by zero, by 14 feet per second and by , we get that the model  for the height of the dog above the ground is:

Then, the time t when the dog land on the ground is calculated replacing by zero and solving for t as:

Now, we have two possible solutions:

or

Taking into account that t=0 is the time when the dog leaps into air, the time when the dog land on the ground is equal to 0.8706 seconds and it is calculated as:

13

step-by-step explanation:

distance formula is d=√(x2-x1)^2   +   (y2-y1)^2

you have orange juice on wednesday. (idk why this is the answer)

step-by-step explanation: