Let Eequals={Bold e 1e1, Bold e 2e2, Bold e 3e3} be the standard basis for set of real numbers Rℝ3, Bequals={Bold b 1b1, Bold b 2b2, Bold b 3b3} be a basis for a vector space V, and T : set of real numbers Rℝ3 right arrow→ V be a linear transformation with the property that Upper T (x 1 comma x 2 comma x 3 )Tx1, x2, x3equals=(x 2 minus x 3 )x2−x3Bold b 1b1plus (x 1 plus x 3 )+x1+x3Bold b 2b2plus (x 2 minus x 1 )+x2−x1Bold b 3b3.a. Find the change-of-coordinates matrix from Upper B to Upper A. b. Find left bracket Bold x right bracket Subscript Upper A for Bold x equals Bold b 1 minus 4 Bold b 2 plus 4 Bold b 3.

22, 28, 34, 40, 46

b)   f(n) = 6n + 16

n = what is the number of the row ( 22 would be row 1) so if we replaced n with 1, we would get 22

c)   the 14th row will have 100 seats

(1)   (2)   (3)   (4)   (5)   (6)   (7)   (8)   (9)   (10) (11) (12) (13) (14)

22 | 28 | 34 | 40 | 46 | 52 | 58 | 64 | 70 | 76 | 82 | 88 | 94 | 100

step-by-step explanation:

hihi so drawing these 2 triangles is fairly simple. all that's left is finding the height of each one. luckily, we have a side length and an angle, so there is a trig function we can use to solve for the height. the easiest one to use would be tangent, since we have 2/3 things needed to find and the third needed is what we are solving for. tan(73°) * 30 ~= 98.13 and tan(73°) * 35 ~= 114.45