Two people swing a jump rope. The highest point in the middle of the jump rope is 76 inches above the ground, and the lowest point is 4 inches. The rope makes 4 revolutions per second. Write a model for the height of the rope in inches as a function of time in seconds given that the rope starts at its lowest point.

h(t) = 36sin(1440x)+ 40

Step-by-step explanation:

Given the information:

y = a sin (bx+c) + k for different values of a, b, and c

=> Amplitude (a) = (highest point - lowest point) / 2 = 36

=> asymptom (k) =  (highest point - lowest point) / 2 = 40

=> model for the height of the rope in inches as a function of time in seconds given that the rope starts at its lowest point is:

h(t) = 36sin(1440x)+ 40

Hope it will find you well.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.