Luther is building a model rocket for a science fair project. He attaches a nose cone to a cylindrical body to
form the rocket's fuselage. The rocket has a diameter of 4 inches and a total height (including the nosecone)
of 19 inches. The nosccone is 7 inches tall. What is the surface area of the rocket?

209.105 in2

Step-by-step explanation:

First we can find the surface area of the cylindrical part, which include the bottom base and the side area, so we have:

S1 = pi*r^2 + 2*pi*r*h

Where S is the surface area, r is the radius and h is the height.

The rocket has a height of 19 inches, and the cone has 7 inches of height, so the cylinder has 19 - 7 = 12 inches of height. The radius is half the diameter, so the radius is 2 inches. Then, we have:

S1 = pi*2^2 + 2*pi*2*12 = 163.3628 in2

For the cone, the surface area (without the base) is given by:

S2 = pi * r * s

where s is the slant height, given by:

s^2 = h^2 + r^2

s^2 = 7^2 + 2^2 = 53

s = 7.2801 in

So we have that:

S2 = pi * 2 * 7.2801

S2 = 45.7422 in2

Summing S1 and S2, we have:

S = S1 + S2 = 163.3628 + 45.7422 = 209.105 in2

mean, 40.6

step-by-step explanation:

option: d is the correct answer.

d) none of the above.

step-by-step explanation:

clearly from the figure attached to the question we could see that there is no shape given. hence without any shape given in the figure and after rotation we can't obtained a square pyramid.

since, to obtain a image we need a proper figure of the pre-image so that it can be transformed.

hence, the correct answer is:

d) none of the above.

step-by-step explanation: