At the present time, Daniel is 8 years older than his cousin William. In two years' time, Daniel will be 3 times older than William is at the present time. How old is Daniel at the present time?

Daniel is 10 years old presently

Step-by-step explanation:

Since we do not know the ages of both people, we assign variables.

Let Daniel’s present age be d while Willam’s present age is w

Daniel is 8 years older;

Mathematically;

d = w + 8 •••••••••••(i)

In two years time Daniel’s age will be d + 2 while William’s age will be w + 2

We know that Daniel will be 3 times as old as Williams will be in these two years time

Mathematically;

d + 2 = 3(w + 2) ••••••• (ii)

From equation 1, we have w = d-8

we substitute this into equation ii

d + 2 = 3(d-8+2)

d + 2 = 3(d-6)

d + 2 = 3d - 18

3d - d = 18 + 2

2d = 20

d = 20/2

d = 10 years

step-by-step explanation:

through just a quick inspection, one can see that the graph of this cubing function starts in quadrant iii and ends in quadrant i.   when x = 0, y = 3, so the y-intercept is (0, 3).

if graphs are part of the problem statement, share them.   .

57.09 minus 7.0435 equals

step-by-step explanation:

just subtrach them both and u get the answer of 50.0465