What are the zeros of the polynomial function F(x) = x3 - 5x2 - 6x?

The zeros are {2, 3}

Step-by-step explanation:

Please use " ^ " to indicate exponentiation:  

F(x) = x^3 - 5x^2 - 6x

Factoring out x, we get:

F(x) = x(x^2 - 5x - 6)

Factoing the quadratic, we get:

F(x) = x(x - 3)(x - 2) = 0

The zeros are {2, 3}

answer: 94

step-by-step explanation: 79+91+92+94+94 = 450 divided by 5 (since there are 5 number that are being added) = 90

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0