The Japanese 5 yen coin has a hole in the middle.
What are the possible ways to calculate the difference
between the distances from the outer edges and the
inner edges of the coin? Check all that apply.
☻︎Subtract the two diameters and multiply by T
☻︎Calculate the circumference of the coin.
☻︎Add the two diameters and multiply by z
☻︎Subtract the circumference of the hole from the
circumference of the coin.
☻︎ Calculate the radius of the hole.

32/80  

91/140

the last one 54 doesn't go into 45. 54/100 ?

step-by-step explanation:

the answer is 2/54

step-by-step explanation:

3

step-by-step explanation:

step by step resolutions

1) n+n+1+n+2=51

3n+3=51

3n=48

n=16

the three numbers are 16, 17 and 18.

2) x+15=4x

3x=15

x=5

radha is now 5 years old

3) the two digits are x and y.

y=3x

(10x+y)+(10y+x)=88

y=3x

11x+11y=88

y=3x

x+y=8

x+3x=8

x=2

the original number can be either 28 or 82.

4) n+(n+2)+(n+4)=48

3n+6=48

3n=42

n=14

the numbers are 14, 16 and 18.

5) y=x+3

10y+x+10x+y=143

y=x+3

11x+11y=143

y=x+3

x+y=13

x+x+3=13

2x=10

x=5

the original number can be 57 or 75.

hope this !