Triangle PQR has vertices P(-2,-1). Q(-1,4), and R(1,3). Triangle P'G'R' has vertices P' (-2,1).& (-1,-4), and R' (1, -3).
Which transformation maps APQR onto A P'O'R', preserving side lengths so that the triangles are congruent by SSS?
O A. reflection over the x-axis
B. reflection over the y-axis
C. reflection over the line y = x
O O
D. rotation 90° clockwise about the origin
E. rotation 180° clockwise about the origin

step-by-step explanation:

ok so im not 100% sure but you would start by adding 5.1t and 1.9t beacuse they have the same variable. that is 7t.   then add -3.6 + 1.2 which is -2.4

so then keep that as -2.4 + 7t. i apologize if this is incorrect. best luck on your test < 3

i think the correct option is the second option.

let's cover over the formula of the vertex:

y = a(x – h)^2 + k

in this formula, (h,k) are the vertex, always remember that the positive or negative value of the vertex is based on the sign it has.

for example, if the vertex is -3,-6 then both the x and y value would have the positive sign attached to it and if it were a positive x and y value, then a negative sign would be attached to it.

with that being said, for our problem the x value is a positive one so we are looking for a number with a negative sign next to it, in this case the first and second choice.

however, for the first answer choice it isn't quite part of the formula so we know that the answer choice correctly displays the x value.

to confirm, we can see if the -1 fits correctly with the second answer choice, and as mentioned above a negative number will have a positive sign attached to it. so, for our problem we can see that -1 has been changed to +1, so we can confirm that the second answer choice is correct.

hence, our final answer is y=(x - 1)^2 + 1

answer: y=0 if that is what u r looking for