We are planning a reception for our daughter. The hall that we are renting charges a $50 cleanup fee. In addition to the cleanup fee, they charge $33 per guest for food and drinks.
If we have $3,300.00 available, what is the maximum number of guest we can invite without going over our budget?

98 guests

Step-by-step explanation:

First, you would take the amount of money available, $3,300.00, and subtract the cleanup fee ($50) from that.

You would get $3,250

Next, you divide $3,250 by the amount of money per guest ($33).

Your total is 98.48 repeated

That rounds to 98 people, since you can't go over.

Hope this helps you!

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.