One approach to active learning is a "flipped classroom." This commonly involves students watching video lectures outside of class and working on problem solving activities in class. Research has primarily focused on comparing teaching approaches using end-of-class outcomes, such as final grades. In a recent project, researchers compared the lasting benefits of a flipped classroom by comparing grades received in the subsequent course of the series. Here are the results:

Groups n I s
Flipped 166 2.45 1.09
Traditional 129 1.59 1.20

Assume the population variances are equal.

Do the average grades received differ across the two delivery styles of the previous course? Use a=0.01.

Yes, they differ across the two delivery styles of the previous course.

Step-by-step explanation:

So, we are given the following data or information or parameters from the question above;

Flipped(group) => 166(n) 2.45(l) 1.09(s).

Traditional(group) => 129(n) 1.59(l) 1.20(s).

Therefore, the hypothesis is given below as; Jo : b1 = b2, Jx : b1 ≠ b2.

Recall that we are given; 166 = (n1), 2.45 = (l1), 1.09 = (s1) and 129 = (n2) , 1.59 = (l2), 1.20 = (s2).

Therefore, we will be using the following mathematical representation or formula to solve this question;

s = √(s1^2/ n1 + s2^2/n2).

When we slot it the values accordingly and solve for s, we will have a value of;

s = 0.1354.

Thus , for our t*, we can calculate that by using the formula below:

t*= l1 - l2/ s.= (2.45 - 1.59)/ 0.1354= 6.35.

Thus: p value = 2P(V> 6.35) = 2.1 × 10^-10.

Since we are given that a=0.01, thus, p value is less than 0.01 we can reject Jo.

(4,5

look up a corrdinate plane and do what the thingy says and boom

his chances of getting a coin of higher value is 4/19

step-by-step explanation: