PLZ HELP

On a coordinate plane, triangle J K L has points (0, negative 1), (negative 2, 1), and (3, 3).

Reflect the triangle over the y-axis and find the coordinate of the image of point K.

K’(2, 1)

K’(–2, 1)

K’(–2, –1)

K’(2, –1)

K'(2, 1 )

Step-by-step explanation:

Under a reflection in the y- axis

a point (x, y ) → (- x, y ), thus

K(- 2, 1 ) → K'(2, 1 )

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.

step-by-step explanation: