Find the zeros of the function h(x)=x^2+23x+60 by factoring.

x = - 20, x = - 3

Step-by-step explanation:

To find the zeros, let h(x) = 0, that is

x² + 23x + 60 = 0

Consider the factors of the constant term (+ 60) which sum to give the coefficient of the x- term (+ 23)

The factors are + 20 and + 3, since

20 × 3 = 60 and 20 + 3 = 23, thus

(x + 20)(x + 3) = 0 ← in factored form

Equate each factor to zero and solve for x

x + 20 = 0 ⇒ x = - 20

x + 3 = 0 ⇒ x = - 3

i think the answer is b.

step-by-step explanation:

not 100% sure though.