Find the perimeter of each polygon. Assume that lines which appear to be tangent are tangent.

The perimeter would be 60 units; Option B

Step-by-step explanation:

~ Let us consider this problem. We know that tangent segments are congruent to one another provided they are from one endpoint. According to that, we would note that several segments are congruent to one another...  ~

1. All the tangent segments that "sprout" from one vertex in this plane onto the circle circumscribed in this triangle are congruent, as noted before. According to that the side of the length 18 units has one part equivalent to 8.7 units.

2. With that being said the other part of the side with length 18 units, would be 18 - 8.7 = 9.3 units. Respectfully the side with length of 21.3 units has a part that is congruent to 9.3, by tangent ≅. This other part of the side with 21.3 units now = 21.3 - 9.3 = 12 units. Similarly the side with 8.7 as a part of it, has the other part ≅ to 12 units, it's measure thus also being 12 units.

3. Let us see the measures we have at this point. The perimeter would be ⇒ 8.7 + 8.7 + 9.3 + 9.3 + 12 + 12 = 60 units

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step-by-step explanation: