Help with this question please1

(-2,8)

Step-by-step explanation:

3x+3y = 18

2x+y = 4

Multiply the second equation by -3

-3(2x+y) = -3*4

-6x-3y = -12

Add this to the first equation

3x+3y = 18

-6x-3y = -12

-3x = 6

Divide each side by -3

-3x/-3 = 6/-3

x = -2

Now solve for y

2x+y = 4

2(-2) +y = 4

-4+y =4

Add 4 to each side

-4+4+y = 4+4

y =8

(-2,8)

Step-by-step explanation:

3x + 3y = 18 (1)

2x + y = 4 (2)

(1) - 3(2)

3x + 3y = 18

-(6x + 3y = 12)

-3x = 6

x = -2

Using (2)

2(-2) + y = 4

-4 + y = 4

y = 8

the size of the resulting matrix is 1-by-3.

step-by-step explanation:

the size of the two matrices given are as follows:

no .of rows of matrix 1 = 1

no .of columns of matrix 1 = 3

no .of rows of matrix 1 = 3

no .of columns of matrix 1 = 3

to find the size of the resulting matrix without actually solving the multiplication of the matrix, this is what you do:

if resulting matrix = matrix 1 * matrix 2

no. of rows of the resulting matrix = number of rows of matrix 1

no. of columns of resulting matrix = number of columns of matrix 2

note: the order of the matrices matter!

the dimensions are:

step-by-step explanation:

we want to find the dimensions of a rectangular box with volume of

we factor to obtain;

we rewrite the rightmost factor to obtain;

recall that:

we apply difference of two squares formula to obtain;

hence the dimensions are