In ΔVWX, v = 47 cm, w = 11 cm and x=38 cm. Find the measure of ∠W to the nearest 10th of a degree.

When we know all 3 sides we use the law of cosines

a = 47  

b = 11  

c = 38

cos (A) = (b^2+c^2-a^2)  / (2bc)

cos (A) = -0.7703349282

Angle A = 140.38

cos (B) = (a^2 + c^2 -b^2) / (2ac)

cos (B) =  0.9888017917

Angle B = 8.5826  degrees

cos (C) = (a^2 + b^2 -c^2) / 2ab

cos (C) = 0.8568665377

cos (C) = 31.033 degrees

Angle W would be the smallest angle so it equals

31.033 degrees or rounded to nearest tenth

31.03

Step-by-step explanation:

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.