In ΔIJK, the measure of ∠K=90°, JK = 90 feet, and KI = 54 feet. Find the measure of ∠I to the nearest tenth of a degree.

9514 1404 393

  ∠I = 59.0°

Step-by-step explanation:

The applicable trig relation is ...

  Tan = Opposite/Adjacent

  tan(I) = JK/KI = 90/54

  I = arctan(90/54) ≈ 59.04°

The measure of angle I is about 59.0°.

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4

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