Sonjia bought a combination lock that opens with a 4-digit number created with the numbers 0 through 9. The same digit cannot be used more than once in the combination. If Sonjia wants the last digit to be 7 and the order of the digits matters, how many ways can the remaining digits be chosen?

If Sonjia wants to create combination as described, by using the permutation formula, the number of ways for remaining digits should be:

N = (10-1)(9-1)(8-1) = 9 x 8 x 7 = 504 ways

Hope this helps!

:)

it has 4

step-by-step explanation:

les

elee

fg

elle

fetish

ser

el

le

f

lent

clee hd

lg

ad

be

hu

te

see

te

ele

cele

her

t

errel

c

s​

70,000 + 6,000 + 800 + 30

step-by-step explanation: