1. A car priced at $25,329 is financed with a simple interest rate of 4.25% for 5 years with no down payment. Payments
of $511.86 are made each month. Another car priced at $22.464 is financed with a simple interest rate of 3.78% for 5
years with a down payment of $2,500. Payments of $395.62 are made each month.
a. For each loan, generate a table, graph, and equation that can be used to represent the balance after the down
payment, if applicable, and the first 12 months of payments. The tables should represent the number of months
in terms of x and the balance of the loan after each month's payment in terms of y.
b. Determine the rate of change, or slope, of each line and state the y-intercepts.
c. Using your generated graph for the first situation, describe how the unit rate of the amount of money paid
monthly is related to the slope of the line.
d. Determine if each relationship represented in the table, graph, and equation represents a proportional or non-
proportional situation
e. Use a set of ordered pairs, table, mapping, or graph to determine if each relationship represents a function.

your answer is a

step-by-step explanation:

plzplzplzplzplz mark brainliest i need it.

14

step-by-step explanation:

i think it's eleven too, don't woosh me here, but according to the "experts" it's 2.

the proof starts from the peano postulates, which define the natural

numbers n. n is the smallest set satisfying these postulates:

  p1.   1 is in n.

  p2.   if x is in n, then its "successor" x' is in n.

  p3.   there is no x such that x' = 1.

  p4.   if x isn't 1, then there is a y in n such that y' = x.

  p5.   if s is a subset of n, 1 is in s, and the implication

      (x in s => x' in s) holds, then s = n.

then you have to define addition recursively:

  def: let a and b be in n. if b = 1, then define a + b = a'

      (using p1 and p2). if b isn't 1, then let c' = b, with c in n

      (using p4), and define a + b = (a + c)'.

then you have to define 2:

  def:   2 = 1'

2 is in n by p1, p2, and the definition of 2.

theorem:   1 + 1 = 2

proof: use the first part of the definition of + with a = b = 1.

      then 1 + 1 = 1' = 2   q.e.d.

note: there is an alternate formulation of the peano postulates which

replaces 1 with 0 in p1, p3, p4, and p5. then you have to change the

definition of addition to this:

  def: let a and b be in n. if b = 0, then define a + b = a.

      if b isn't 0, then let c' = b, with c in n, and define

      a + b = (a + c)'.

you also have to define 1 = 0', and 2 = 1'. then the proof of the

theorem above is a little different:

proof: use the second part of the definition of + first:

      1 + 1 = (1 + 0)'

      now use the first part of the definition of + on the sum in

      parentheses:   1 + 1 = (1)' = 1' = 2   q.e.d.