What is the probability of rolling a die 6 times and getting the numbers 1, 2, 3, 4, 5, 6 in that order? Select the best answer from the choices provided.
A. 0.001389
B. 0.000129
C. 0.000021
D. 0.0000038

C. 0.000021

Step-by-step explanation:

Each roll of the die is an independent event.

The probability of rolling a 1, then a 2, then a 3, then a 4, then a 5, then a 6 is the product of the 6 individual probabilities.

Probability of rolling a 1:

There are 6 possible outcomes, rolling 1, 2, 3, 4, 5, or 6.

There is one desired outcome, rolling a 1.

p(1) = 1/6

Probability of rolling a 2:

Similar to rolling a 1, there is 1 desired outcome,rolling a 2, out of 6 possible outcomes.

p(2) = 1/6

The same is true for rolling a 3, 4, 5, or 6. Each one has a probability of 1/6.

p(1, 2, 3, 4, 5, 6, in that order) = p(1) * p(2) * p(3) * p(4) * p(5) * p(6)

= (1/6)^6

= 1/6 * 1/6 * 1/6 * 1/6 * 1/6 * 1/6

= 1/46,656

= 0.000021433

C. 0.000021

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

what statement? is there an image?