A farmer has a maximum of 80m² of
farmland to cultivate for soya beans and maize. Altogether, he does not want to
spend more than ₦870 in cultivating the entire farmland. He spends ₦9 per m² for soya
beans and ₦2 per m² for maize. Assuming
that he cultivates xm² of the land for soya
beans and ym² of the land for maize
(a) write down all the inequalities
connecting x and y:
(b) show by shading the region which
satisfies the set of inequalities in (a);
(e) if the farmer makes a profit of N 25
per m² for soya beans and
N30 per m² for maize, find the values
of x and y that maximize the profit

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

28

step-by-step explanation:

because that's the answer