(3x^3+4x^2) -(2x^3+3x^2-x)=(3x 3 +4x 2 )−(2x 3 +3x 2 −x)

x = 0 or x = sqrt(21)/2 - 1/2 or x = -1/2 - sqrt(21)/2

Step-by-step explanation:

Solve for x over the real numbers:

(3 x^3 + 4 x^2) - (2 x^3 + 3 x^2 - x) = (3 3 x + 4 2 x) - (2 3 x + 3 2 x - x)

(3 x^3 + 4 x^2) - (2 x^3 + 3 x^2 - x) = x^3 + x^2 + x and (3 x 3 + 4 x 2) - (2 x 3 + 3 x 2 - x) = 6 x:

x^3 + x^2 + x = 6 x

Subtract 6 x from both sides:

x^3 + x^2 - 5 x = 0

Factor x from the left hand side:

x (x^2 + x - 5) = 0

Split into two equations:

x = 0 or x^2 + x - 5 = 0

Add 5 to both sides:

x = 0 or x^2 + x = 5

Add 1/4 to both sides:

x = 0 or x^2 + x + 1/4 = 21/4

Write the left hand side as a square:

x = 0 or (x + 1/2)^2 = 21/4

Take the square root of both sides:

x = 0 or x + 1/2 = sqrt(21)/2 or x + 1/2 = -sqrt(21)/2

Subtract 1/2 from both sides:

x = 0 or x = sqrt(21)/2 - 1/2 or x + 1/2 = -sqrt(21)/2

Subtract 1/2 from both sides:

x = 0 or x = sqrt(21)/2 - 1/2 or x = -1/2 - sqrt(21)/2

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

answer: im sorry i dont get it

step-by-step explanation: