A 20-meter long cable is used to support a telephone pole, holding the pole to make the pole perpendicular to the ground. If the cable forms a 60°
60
°
angle with the ground, how high up the pole should the cable be attached?

17.32m

Step-by-step explanation:

The shape formed by the arrangement between the pole, the ground and the wire is that of a right angled triangle.

Given that the cable forms 60° with the ground, the Pole is the opposite side of the triangle, the ground is the adjacent and the length of the supporting cable is the hypotenuse side.

Using the SOH CAH TOA notation, let the length of the point of attachment of the pole to the cable be x

Sin 60° = x/20

x = 20 Sin 60°

= 20 * 0.8660

= 17.32m

answer: y=4000x+14000

step-by-step explanation:

any options?

step-by-step explanation: