Mathematics, 03.10.2019 00:30 raenfall455
Find a so that the point (-1, 2) is on the graph of f(x)=ax^2+5.
Answers: 1
Mathematics, 21.06.2019 23:00
36x2 + 49y2 = 1,764 the foci are located at: (-β13, 0) and (β13,0) (0, -β13) and (0,β13) (-1, 0) and (1, 0)edit: the answer is (- the square root of 13, 0) and (the square root of 13, 0)
Answers: 1
Mathematics, 21.06.2019 23:00
Either enter an exact answer in terms of \piΟ or use 3.143.14 for \piΟ and enter your answer as a decimal.
Answers: 2
Mathematics, 22.06.2019 03:00
Define the type of sequence below. -2,0,2,4,6 a. both arithmetic and geometric b. arithmetic c. neither arithmetic nor geometric d. geometric
Answers: 3
Find a so that the point (-1, 2) is on the graph of f(x)=ax^2+5....
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