What is the measure of arc AD?

Angle ABD measures (4x + 10). Angle ACD measures

(5x - 2)

GO

116°

Step-by-step explanation:

Given that :

∠ ABD measures (4x + 10)

∠ ACD measures  (5x - 2)

Then

∠ABD = ∠ACD  ( rule : angle by same chord AD )

∠ABD =   (4x + 10)°

∠ACD =   (5x - 2)°

so we can as well say that :

(4x + 10)° = (5x - 2)°

4x - x = -10 -2

- x = - 12

x   = 12

∠ABD = (4x + 10)°

= ( 4 × 12 + 10)°

= 58°

∠ACD = (5x - 2)°

= ( 5 * 12 - 2)°

= 58°

∠AOD = 2∠ABD = 2∠ACD   ( since angle by arc AD at  center is  twice the  angle by same arc AC in other arc segment)

 ∠AOD =  2 × 58°

∠AOD = 116°

Measure of arc AD = 116°

4sqrt5

step-by-step explanation:

the base has dimensions of 8 x 4, so the diagonal is 64 + 16 square rooted or 4sqrt5.

this doesn't make sense lol