A veterinary clinic is receiving complaints from dog owners that they have to wait longer than cat owners to have their pets seen. as pets enter the clinic, the time that they arrive until the time that they are seen by a vet ("wait time") is recorded. a random sample of 150 cats and dogs is selected; statistics regarding the wait times for each pet is summarized in the table below. do the data provide convincing statistical evidence that the mean wait time for dogs is significantly longer than the mean wait time for cats

if you need just tell me and i will come to the rescue.

step-by-step explanation:

she will travel a distance in the range of 3 - 11 miles

b

step-by-step explanation:

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)