The length of a rectangle is 5 inches more than the width. The area is 33 square inches. Find the length and width . Round to the nearest tenth if necessary.

the length and width . Round to the nearest tenth are 8.8 inches and 3.8 inches respectively.

Step-by-step explanation:

The area A of a rectangle is the product of the length L and width W. This may be expressed mathematically as

A = L * W

As such, given that the length is 5 inches more than the width,

L = W + 5

33 = W(W + 5)

W² + 5W  - 33 = 0

Using the formula method which states that

s = -b±√(b²-4ac)/2a

W = -5 ± √5² - 4(1)(-33)/2

= -5 ± 12.53/2

= 7.53/2 (since length cannot be negative)

= 3.755 inches

L = 3.755 + 5

= 8.755 inches

10a^3+277a^2-132a-792

step-by-step explanation:

(2a+11)(5a-12)(foil)

=10a^2-24a+55a-132 =10a^2+31a-132

(10a^2+31a-132)(a+6)

=10a^3+60a^2+31a^2+186a^2-132a-792 =10a^3+277a^2-132a-792

i hope this is what you are looking for : )

answer is 144

step-by-step explanation: