Marble Slab Creamery is creating a cone-shaped paper wrapper for its new green Baby Yoda waffle cone. The wrapper should have a radius of 5 cm and a slant height of 10 cm. One location wants to offer the cones a weekend earlier, so they plan to make the cone-shaped wrappers for first 25 waffle cones sold that Saturday. About how many square cm of wrapper paper will they need? (Round up to the nearest cm.)

3927 cm² wrapping paper will be required.

Step-by-step explanation:

Lateral surface area of a cone shaped wrapper = πrl

where, r = radius of the waffle cone

and l = slant height of the cone

It has been given in the question, radius 'r' = 5cm

and lateral height 'l' = 10 cm

Lateral surface area of the cone = π(5)(10)

                                                      = 50π

                                                      = 157.08 cm²

If they plan to make 25 waffles then wrapper paper required

= 25×157.08

= 3927 cm²

Therefore, 3927 cm² wrapping paper will be required.

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

what are the answer choices given for this problem?