A square rug has an inner square in the center. The side length of inner square is x inches and the width of the outer region is 2 inches. What is the area of the outer part of the rug?

so Area of Outer part = 8x + 16 square inches

Step-by-step explanation:

2 squares.

inner square dimension is  x inches by x inches.

width of outer region= 2inches.

We want the area of the border around the inner square.

so

Area of border = B  =  Area of Large - Area of Inner

B = (x+4)^2  - x^2

B = x^2 + 8x + 16 -  x^2

B = 8x + 16  square inches

so Area of Outer part = 8x + 16 square inches

13

step-by-step explanation:

169-1=168

168-3=165

165-5=160

160-7=153

153-9=144

144-11=133

133-13=120

120-15=105

105-17=88

88-19=69

69-21=48

48-23=25

25-25=0

since it took 13times to completely subtract it hence its square root is 13