A normal distribution has a mean of 186.4 and a standard deviation of 48.9.

What range of values represents the upper 2.5% of the data?

a

X > 235.3

b

X > 333.1

c

X > 284.2

d

X > 186.4

We have been given that a normal distribution has a mean of 186.4 and a standard deviation of 48.9. We are asked to find the range of value that represents the upper 2.5% of the data.

We know that upper 2.5% of data would be 97.5% of data.

We will use z-score formula to solve our given problem.  

, where,

z = z-score,

x = Random sample score,

= Mean,

= Standard deviation.

Now we will use normal distribution table to find z-score corresponding to 97.5% area or 0.975.

We can see from the normal distribution table that z-score corresponding to  area 0.975 is .

Let us solve for x.

Therefore, the range represents the upper 2.5% of the data.

the answer is c. hope this !

step-by-step explanation:

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.