Write an indirect proof to show that the diagonals of a parallelogram bisect one another. be sure to create and name the appropriate geometric figures.

 parallelogram ABCD 
AC and BD are diagonals  
AC and BD intersect at point E 

AB is parallel to CD | opposite sides of a parallelogram are parallel 

AB = CD | are congruent opposite sides of a parallelogram  
angle BAC = angle DCA |interior angles of parallel lines 
angle ABD = angle CDB |interior angles of parallel lines 

Triangle ABE = Traingle CDE | ASA 
EA = EC | corresponding sides of congruent triangles are congruent. 
E bisects AC| AE = EC
                                     hope its help

I’m not absolutely sure but i think it’s 7x6x5x4x3x2=5040 because as the first character you can take any of the 7 given then you are left with 5 then 6 then 4 etc.