Three letters are chosen at random from the letters p, a, n, s, o, l. what is the size of the sample space of this experiment? assume that the order of the letters matters. that is, pan is different from apn

You need to find the number of permutations of the 6 different letters, taken 3 at a time.

Therefore the sample space is 120 possible outcomes.

Answerthe simplified expression isexplanationthe given expression is,let us deal with the bracket first.the two negatives in the parenthesis will become positive.the expression now becomes,we now expand the parenthesis to get,we group like terms to obtain,this simplifies to,