What are the zeros of the quadratic function f(x) = 2x2 – 10x – 3? x = StartFraction negative 5 Over 2 EndFraction – StartFraction StartRoot 31 EndRoot Over 2 EndFraction and x = StartFraction negative 5 Over 2 EndFraction + StartFraction StartRoot 31 EndRoot Over 2 EndFraction x = StartFraction negative 5 Over 2 EndFraction – StartFraction StartRoot 37 EndRoot Over 8 EndFraction and x = StartFraction negative 5 Over 2 EndFraction + StartFraction StartRoot 37 EndRoot Over 8 EndFraction x = StartFraction 5 Over 2 EndFraction – StartFraction StartRoot 31 EndRoot Over 2 EndFraction and x = StartFraction 5 Over 2 EndFraction + StartFraction StartRoot 31 EndRoot Over 2 EndFraction x = StartFraction 5 Over 2 EndFraction – StartFraction StartRoot 37 EndRoot Over 8 EndFraction and x = StartFraction 5 Over 2 EndFraction + StartFraction StartRoot 37 EndRoot Over 8 EndFraction Mark this and return

the circle graph is not a function.

step-by-step explanation:

the graph of the circle is not a function.

because for a graph to be a function, each value of x must give one value of y

in the circle, the values of x for -2< x< 2 each give 2 values of y.

hence this is not a function.

stops on an even number.

starting with:    

5 + x - 12 = 2x - 7   

5 + x - 12 - x = 2x - 7 - x (subtract x from both sides)   

5 - 12 = x - 7 (combine and cancel x's from both sides)   

5 - 12 + 7 = x - 7 + 7 (add 7 to both sides)   

0 = x (add numbers together on both sides)       

so in order for the equation to be true, x must be 0.   

trying x = -0.5   

5 + x - 12 = 2x - 7 (original equation)   

5 + -0.5 - 12 = 2(-0.5) - 7 (plug in value of x)   

5 + -0.5 - 12 = -1 - 7 (did multiplication)   

-7.5 = -8 (did addition on both sides)       

since -7.5 is obviously not equal to -8, the value of -0.5 for x is wrong.   

trying x = 0   

5 + x - 12 = 2x - 7 (original equation)   

5 + 0 - 12 = 2(0) - 7 (plug in value of x)   

5 + 0 - 12 = 0 - 7 (did multiplication)   

-7 = -7 (did addition on both sides)       

since -7 equals -7, that demonstrates that the value of 0 for x is correct.   

trying x = 1   

5 + x - 12 = 2x - 7 (original equation)   

5 + 1 - 12 = 2(1) - 7 (plug in value of x)   

5 + 1 - 12 = 2 - 7 (did multiplication)   

-6 = -5 (did addition on both sides)       

since -6 is obviously not equal to -5, the value of 1 for x is wrong.

p = 6s

step-by-step explanation: