Which are the coordinates of the vertices of the reflected figure when triangle ABC is reflected across the x-axis? 100 POINTS
A'(–5, –3)
B'(3, –2)

C'(–2, –2)

A'(–5, –3) B'(3, –2)
C'(2, 2)

A'(5, 3) B'(3, –2)
C'(2, 2)

A'(5, 3) B'(–3, 2)
C'(–2, –2)

Notice that since the line of reflection was the x-axis, the x-coordinate of each vertex stays the same and the y-coordinate of each vertex is the opposite of the original vertex, so in that case, the answer is

Option 4 or D.

Plz mark brainliest thxx

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)