A park ranger spent $208 to buy 12 trees.
Redwood trees cost $24 each and
spruce trees cost $16 each. How many of
each tree did the park ranger buy?

Let x represent number of redwood trees and y represent number of spruce trees.

We have been given that a park ranger bought 12 trees. We can represent this information in an equation as:

We are also told that redwood trees cost $24 each, so cost of x redwood trees would be .

Each spruce tree costs $16, so cost of y spruce trees would be .

Since the park ranger spent $208 on trees, so we can represent this information in an equation as:

Upon substituting equation (1) in equation (2), we will get:

Therefore, the park ranger bought 2 redwood trees.

Upon substituting in equation (1), we will get:

Therefore, the park ranger bought 10 spruce trees.

tickets for the harlem globetrotters

show at michigan state university in

2010 cost $16, $23, or, for vip seats, $40.

total revenue = 16x + 23y + 40z

if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, if 9 times as many $16 tickets were sold

as vip tickets,

x = 9z => x – 9z = 0, sales of all three kinds of tickets would

total $46,575.

16x + 23y + 40z = 46575, how many of each kind of ticket would

have been sold?

solve for x, y and z

x − 9z = 0

x − y − z = 55

16x + 23y + 40z = 46575

x = 1170

y = 985

z = 130

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