subject
Mathematics, 06.05.2020 17:01 phanuel642

Jerome solved the equation 1

3

x + 5

6

= 1 as shown.

1. Subtraction property

of equality: 1

3

x + 5

6

βˆ’ 5

6

= 1

1

βˆ’ 5

6

2. LCD: 1

3

x = 1

6

βˆ’ 5

6

3. Multiply by the

reciprocal: ( 3

1

) 1

3

x = βˆ’4

6

( 3

1

)

4. Solve and simplify: x = βˆ’12

6

= βˆ’2

Analyze Jerome’s steps. In which step did he make an error?

In step 1, he needed to add StartFraction 5 Over 6 EndFraction to both sides of the equation.

In step 2, the LCD was not used correctly to make equivalent fractions.

In step 3, the correct reciprocal was not multiplied to both sides.

In step 4, the answer was not reduced correctly.

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Answers: 2

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Jerome solved the equation 1

3

x + 5

6

= 1 as shown....
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