Yet another variation: A better packet switched network employs the concept of acknowledgment. When the end user’s device receives a packet correctly it sends an acknowledgment to the sender. Here too, a packet is received correctly with probability p, but the sender keeps sending copies of a given packet until a copy is correctly received (signaled by acknowledgment). Let random variable N be the number of times the same message packet is sent. a) Find the PMF PN (n).

P(N = n) =  

Step-by-step explanation:

to find out

Find the PMF PN (n)

solution

PN (n)

here N is random variable

and n is the number of times

so here N random variable is denote by the same package that is N (P)

so here

probability of N is

P(N ) = Ф ( N = n)          ..................  1

here n is = 1, 2,3, 4,...................... and so on

so that here P(N = n) will be

P(N = n) =  

let soccer = x and golf = y

part a

1st equation: x + y = 125

2nd equation: x = y +45

part b

replace x in the 1st equation with the 2nd one:

y + 45 + y = 125

simplify:

2y + 45 = 125

subtract 45 from each side:

2y = 80

divide both sides by 2:

y = 80/2

y = 40

she plays golf for 40 minutes.

part c

no because she plays soccer for 45 minutes longer than golf 40 +45 =   85 minutes, not 80 minutes.

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length