Metacritic is a website that aggregates reviews of music, games, and movies. For each product, a numerical score is obtained from each review and the website posts the average core as well as individual reviews. The website is somewhat similar to Rotten Tomatoes, but Metacritic uses a different method of scoring that converts each review into score in 100-point scale. In addition to using the reviewers quantitative ratings (stars, 10-point scale), Metacritic manually assesses the tone of the review before scoring. Historical data shows that these converted scores are normally distributed. One of the movies that the Metacritic rated was Zootopia. Based on the data from Metacritic on November 20, 2017, there are n=43 reviews, the sample average score is 77.86, and the sample standard deviation is 11.30.
A 95% confidence interval for the true average score (µ) of Zootopia is:

a) [75.21, 81.50]
b) [76.38, 80.34]
c) [77.15, 82.84]
d) [78.96, 81.76]
e) None of the above

e) None of the above

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 43 - 1 = 42

95% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 42 degrees of freedom(y-axis) and a confidence level of . So we have T = 2.0181

The margin of error is:

M = T*s = 2.0181*11.3 = 22.80

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 77.86 - 22.8 = 55.06

The upper end of the interval is the sample mean added to M. So it is 77.86 + 22.8 = 100.66.

So the correct answer is:

e) None of the above

it's both, now can you answer my most recent question?

it would more likely be bald eagle because its has more in the box so about 75%.

step-by-step explanation: