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Mathematics, 06.05.2020 03:42 dontcareanyonemo

PLEASE HELP ASAP, I appreciate it.
Find the equation of a parabola with vertex (2, -1), opens upward and has a focal width of 16.

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Answers: 3
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Answer from: Quest

for this case we have by definition, if two lines are perpendicular, then the product of their slopes is -1.

m_ {1} * m_ {2} = - 1

then, given the following line:

6x-3y = 18\\6x-18 = 3y

\frac {6x} {3} - \frac {18} {3} = y\\y = \frac {6x} {3} - \frac {18} {3}\\y = 2x-6

so, m_ {1} = 2

we are looking for m_ {2}:

m_{2}=\frac{-1}{m_{1}}\\m_{2}=\frac{-1}{2}\\m_{2}=-\frac{1}{2}

then, the line is given by:

y = - \frac {1} {2} x + b

we find "b" replacing the given point:

8 = - \frac {1} {2} (0) + b\\8 = b

finally, the equation is:

y = - \frac {1} {2} x + 8

option c

Me it is a geometry question and you

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