I don’t understand how to do this problem

First find the area of the sector, which includes the shaded region's area and the area of the triangle JKL. Let be the area of the sector. This area occurs in a fixed ratio with the area of the entire circle based on the measure of the central angle subtended by the arc LK:

To get the area of the shaded region, subtract from the area of the triangle.

The area of a triangle is 1/2 the base times the height. If we bisect the central angle with a line segment that meets the side KL at its midpoint, then we get a right triangle with hypotenuse 27 and one angle of measure 27º (half of the central angle). This triangle has base and height such that

So the right triangle has area approximately 1/2*12.258*24.057, or about 147.443. Triangle JKL is made up of two of these right triangles, so it has area of 294.887.

Subtracting this from gives an area of the shaded region of about 48.472, which we round up to 48.5.

its 69.420

step-by-step explanation:

yes because there is exactly one y value for every x value

for function there can't be more than one value for every x value