Nikhil drew a picture of an open greeting card on his paper. A figure can be broken into a rectangle and parallelogram. The rectangle has a base of 5 inches and height of 4 inches. The parallelogram has a base of 5 inches and height of 3 inches. What is the total area of the drawing of the open greeting card? 20 Inches squared 35 Inches squared 40 Inches squared 55 Inches squared

For every corresponding pair of cross sections, the area of the cross section of a sphere with radius r is equal to the area of the cross section of a cylinder with radius and height 2r minus the volume of two cones, each with a radius and height of r. a cross section of the sphere is and a cross section of the cylinder minus the cones, taken parallel to the base of cylinder, is the volume of the cylinder with radius r and height 2r is and the volume of each cone with radius r and height r is 1/3 pie r^3. so the volume of the cylinder minus the two cones is therefore, the volume of the cylinder is 4/3pie r^3 by cavalieri's principle. (fill in options are: r/2- r- 2r- an annulus- a circle -1/3pier^3- 2/3pier^3- 4/3pier^3- 5/3pier^3- 2pier^3- 4pier^3)