A tobacco company claims that its best-selling cigarettes contain at most 40 mg of nicotine. The average nicotine content from a simple random sample 15 cigarettes is 42.6 mg with a standard deviation (s) of 3.7 mg. Is this evidence the nicotine content of the cigarettes exceeds 40 mg? Assume cigarette nicotine content is distributed normally. Use a 1% level of significance (α=0.01) to carry out the appropriate test of significance.

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

Step-by-step explanation:

Information provided

represent the average nicotine content

represent the sample standard deviation

sample size  

represent the value to check

represent the significance level for the hypothesis test.  

t would represent the statistic

represent the p value for the test

System of hypothesis

We want to verify if the nicotine content of the cigarettes exceeds 40 mg , the system of hypothesis are:  

Null hypothesis:  

Alternative hypothesis:  

The statistic for this case would be:

 (1)  

And replcing we got:

The degrees of freedom are:

The p value would be:

We see that the p value is lower than the significance level given of 0.01 so then we can conclude that the true mean for the nicotine content is significantly higher than 40 mg

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

i got so much points from yo a.