For what value of b does (1/12)^-2b times 12^-2b+2=12?

-1/2
-1/4
1/4
no solution

Always remember

Step-by-step explanation:x^-m=1/x^m

1/12=12^-1

also

(x^m)^n=x^(mn)

also (x^m)(x^n)=x^(m+n)

( \frac{1}{12} )^{-2b}(12)^{-2b+2}=12

( 12^{-1})^{-2b}(12)^{-2b+2}=12

( 12^{2b})(12)^{-2b+2}=12

12^{2b-2b+2}=12

12²=12

so no solution

No solution is right

Step-by-step explanation:

the answer is 9.8975

explanation:

when you multiply the "39.59" with the 25% it reduces it and shows its final discounted price. hope this !

step-by-step explanation:

step-by-step explanation:

given that ab is divided into equal parts as

ac, cd, de, ef, fg, gh, hi, ib.

from this we find that f is the midpoint of ab.

so using mid point formula we find

f = (3,7)

similarly considering fb, we get

h = mid point of fb = ((6,6) and g, mid point of fh is

g = (9/2, 13/2)

i is mid point of hb

so i =(15/2,11/2)