The angle θ1\theta_1 θ 1 theta, start subscript, 1, end subscript is located in Quadrant II\text{II} II start text, I, I, end text , and cos⁡(θ1)=−211\cos(\theta_1)=-\dfrac {2}{11} cos(θ 1 )=− 11 2 cosine, left parenthesis, theta, start subscript, 1, end subscript, right parenthesis, equals, minus, start fraction, 2, divided by, 11, end fraction . What is the value of sin⁡(θ1)\sin(\theta_1) sin(θ 1 ) sine, left parenthesis, theta, start subscript, 1, end subscript, right parenthesis ?

The sine of an angle θ is positive in quadrant II, and the value of sine θ is

The given parameters are:

Using trigonometry ratio, we have:

Substitute

Evaluate the square

Subtract 4/121 from both sides

Take LCM

Simplify the numerator

Take square roots of both sides

This gives

From the question, we understand that angle θ is located in quadrant II.

The sine of an angle θ is positive in quadrant II

So, we have:

Hence, the value of sine θ is

Read more about quadrants at:

link

Step-by-step explanation:

Given that the angle  is located in Quadrant II; and

In Quadrant II, x is negative and y is positive.

To find , we first determine the opposite angle of .

This will be done using the Pythagoras theorem.

Therefore:

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

answer: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.

step-by-step explanation: if you weigh 60 pounds on earth, on the moon you will weigh about 10 pounds. if you weigh 120 pounds on earth, you will weigh about 20 pounds on the moon. since weight is caused by the mass of two objects that are near each other, the bigger the objects, the more the force of gravity.