Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean of 1085 and standard deviation of 52. Grade 2 has 15 observations yielding a sample mean of 1034 and standard deviation of 61. Assume the populations to be approximately normal with equal variances.

State and conclude your hypothesis at the 0.05 level of significance if grade 1 and grade 2 true means are equal each other?

Find P-Value.

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

Step-by-step explanation:

Data given

sample mean for group 1

sample mean for group 2

sample size for group 1

sample size for group 2

sample deviation for group 1

sample deviation for group 2

Solution

We want to check if the two means are equal so then the system of hypothesis are:

Null hypothesis:

Alternative hypothesis:

And the statistic is given by:

And replacing we got:

The degrees of freedom are given by:

And the p value would be:

Since the p value is lower than the significance level we have enough evidence to conclude that the true means are different at 5% of significance

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204

idk

step-by-step explanation:

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