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Mathematics, 05.05.2020 15:48 alonzoyt0

In triangle ABC, the angle bisector of < BAC meets line segment BC at D, such that AD = AB. Line segment AD is extended to E such that CD = CE and angles DBE = BAD. SHow that triagnle ACE is iscocles.


In triangle ABC, the angle bisector of < BAC meets line segment BC at D, such that AD = AB. Line

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In triangle ABC, the angle bisector of < BAC meets line segment BC at D, such that AD = AB. Line...
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