Petrich is wrapping four presents for his mom, dad, sister, and daughter. The following are
the estimate box sizes:
- 8.5" × 14.5" × 1.5"
- 9.5" × 14.5" × 2"
- 11" × 16" × 3"
- 15.5" × 12" × 4"
A standard roll of wrapping paper is 30" long with nine feet (three yards) of paper.
Determine the minimum amount of rolls of wrapping paper that Petrich needs for all four
presents. Justify your answer.

Minimum of 12 rolls of wrapping paper

Step-by-step explanation:

Before we can calculate the minimum amount of rolls of wrapping paper that Petrich needs for all four presents, we need to know the volume of each box wrapped.

For box with dimension

- 8.5" × 14.5" × 1.5"

Volume = 185.875in³

For box with dimension

- 9.5" × 14.5" × 2"

Volume = 275.5in³

For box with dimension

- 11" × 16" × 3"

Volume = 528in³

For box with dimension

- 15.5" × 12" × 4"

Volume = 744in³

If a standard roll of wrapping paper is 30" long with nine feet (three yards) of paper

Number of rolls needed for all four boxes = Total volume of all boxes/standard roll

Total volume of boxes = 185.87+275.5+528+744

= 1733.37in³

Dimension of standard roll = 30in+9feet

Since 1foot = 12inches

9feet = 9×12 = 108inches

Dimension of standard roll = 30+108

= 138inches

Number of rolls needed for all four boxes = 1733.37/138

= 12.56

Approximately 12 rolls of wrapping paper is needed by Petrich for all the four boxes.

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.